Posted by **kelly** on Sunday, May 22, 2011 at 10:14pm.

what is the F-^1

of

6/x+4

- pre-calculus -
**drwls**, Monday, May 23, 2011 at 6:54am
Your notation is confusing and your equation is ambiguous without parentheses.

If F(x) = 6/(x+4) = y,

the inverse function F^-1 (x) is the operation that, if applied to y, will give you x.

x +4 = 6/y

x = (6/y) -4

Finally, switch variables.

F^-1(x) = (6/x) - 4

Note that if you apply this inverse function to 6/(x+4), you get back x.

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