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posted by roshunda on Sunday, May 22, 2011 at 9:29pm.

please shoe me how to factor this problem b^3-4b^2-9b+36

use "grouping" b^3-4b^2-9b+36 = b^2(b-4) - 9(b-4) = (b-4)(b^2-9) = (b-4)(b+3)(b-3)

x3 + 2x2 + x + 2

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