what is the molarity of a solution containing 15.0 g of NaCl in 1.25 L of solution?
Convert 15.0 g NaCl to moles. moles = grams/molar mass. Then Molarity = moles/L soln.
.24
To find the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). Let's calculate it step by step:
Step 1: Convert the given mass of NaCl to moles.
The molar mass of NaCl is 58.44 g/mol.
Number of moles of NaCl = (mass of NaCl) / (molar mass of NaCl)
= 15.0 g / 58.44 g/mol
Step 2: Calculate the molarity (M) of the solution.
Molarity = (moles of solute) / (volume of solution in liters)
= (moles of NaCl) / (volume of solution in liters)
= (moles of NaCl) / (1.25 L)
Now let's substitute the values and calculate the molarity.
Molarity = (15.0 g / 58.44 g/mol) / 1.25 L
Using a calculator to perform the calculations:
Molarity ≈ 0.357 M
Therefore, the molarity of the solution containing 15.0 g of NaCl in 1.25 L of solution is 0.357 M.
To calculate the molarity of a solution, you need to know the moles of the solute (NaCl) and the volume of the solution in liters.
First, you need to convert the mass of NaCl into moles. To do this, you divide the mass by the molar mass of NaCl.
The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.
So, moles of NaCl = mass of NaCl / molar mass of NaCl
moles of NaCl = 15.0 g / 58.44 g/mol
Now, you need to convert the volume of the solution from milliliters (mL) to liters (L). Since 1 L is equal to 1000 mL, you divide the volume by 1000.
Volume of solution = 1.25 L / 1000
Finally, you can calculate the molarity of the solution by dividing moles of NaCl by the volume of the solution in liters.
Molarity = moles of NaCl / volume of solution
Now, let's plug in the values:
moles of NaCl = 15.0 g / 58.44 g/mol
volume of solution = 1.25 L / 1000
Molarity = (15.0 g / 58.44 g/mol) / (1.25 L / 1000)
Calculating this expression will give you the molarity of the solution containing 15.0 g of NaCl in 1.25 L of solution.