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April 1, 2015

April 1, 2015

Posted by **Denice** on Sunday, May 22, 2011 at 4:00pm.

(x+3)/(3x^2)/(6x^2)/[(x+3)^2]

- Advanced algebra -
**Reiny**, Sunday, May 22, 2011 at 4:18pmaccording to the order of operation,

in a chain of division, you divide from left to right, in the order in which the division occurs.

e.g.

13÷2÷6÷4 = .25

or

= 12*(1/2)*(1/6)*(1/4) = .25

so How do i simplify this complex fraction?

(x+3)/(3x^2)/(6x^2)/[(x+3)^2]

= (x+3) (1/(3x^2)(1/6x^2)(1/(x+3)^2

= 1/(18x^4(x+3))

- Advanced algebra -
**Denice**, Sunday, May 22, 2011 at 4:29pmIsn't there a different method you're sposed to use? like finding a common denominator? im thankful that your helping me but all those number got a little confusing... what if i said it looked more like this

the dash mark is a division symbol... this is what it looks like on my paper.

x+3

-----

3x^2

------

6x^2

------

(x+3)^2

- Advanced algebra -
**Reiny**, Sunday, May 22, 2011 at 4:44pmYou don't need common denominators in division or multiplication.

If the fraction is written as a staggered layer of expressions, the division bar should have different length to establish the order of division.

If all the bars are the same length, then the simplification I used above is valid

In other words, the longest bar determines the prime division.

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