Wednesday

November 26, 2014

November 26, 2014

Posted by **PRERANA** on Sunday, May 22, 2011 at 9:57am.

lim (existing from n to infinity)1/n^2 [1/1+cos(pie/2n) +2/1+cos(2pie/2n) + 3/1+cos(3pie/2n)+......to n terms]

**Answer this Question**

**Related Questions**

Calculus grade 12 - solve for (<_ = less than or equal to / pie = pie sign...

pre-cal - Simplify the given expression........? (2sin2x)(cos6x) sin 2x and cos ...

Mathematics - Trigonometric Identities - Let y represent theta Prove: 1 + 1/tan^...

Advance Math - Find solutions of the equation in the interval [0, 2pie} Cos(x+...

Math (College Level Mathematics) - Fourier cosine series correspondence for f(x...

maths - Choose the two options which are true for all values of x 1) cos (x) = ...

calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...

Calc. - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x ln...

math - Determine exact value of cos(cos^-1(19 pi)). is this the cos (a+b)= cos a...

trig - If tan A = 2 and A belongs to [pie,3pie/2] then the expression cos A ...