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October 22, 2014

October 22, 2014

Posted by **GoMeGo** on Sunday, May 22, 2011 at 1:05am.

This is due tomorrow.

- Trig -
**Reiny**, Sunday, May 22, 2011 at 8:43amDraw a vector AB , S15°E, showing the boat in still water.

Draw BC, going West, showing the speed of the river.

Join AC , the resultant vector.

By simple calculation of angles,

angle A = 26°

angle B = 75°

angle C = 79°

I see two simple applications of the sine law

for the speed of the river:

a/sin26° = 25/sin75°

a = 25sin26/sin75 = 11.35

for the boat's speed in still water:

c/ain79 = 25/sin75

c = 25.406

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