Matt forgot to put the fabric softener in the wash. As his socks tumbled in the dryer, they became charged. If a small piece of lint with a charge of +1.25 E -19 C is attracted to the socks by a force of 3.0 E -9 N, what is the magnitude of the electric field at this location?

Suppose an electric field with a magnitude of 2.8 E 4 N/C at a certain location, points due south. If a charge of -4.0 E -6 C is brought to the location, what is the electrostatic force that acts on this charge?

force=qE

To find the magnitude of the electric field at a location where a small piece of lint is attracted to charged socks, we can use the formula:

Electric field strength (E) = Force (F) / Charge (q)

Given:
Force (F) = 3.0 E -9 N
Charge (q) = +1.25 E -19 C

Substituting the values into the formula, we have:

E = F / q
E = (3.0 E -9 N) / (1.25 E -19 C)

To simplify the calculation, we can divide the numbers separately and the exponents separately:

E = (3.0 / 1.25) × (10^(-9-(-19)))
E = 2.4 × 10^10 N/C

Therefore, the magnitude of the electric field at this location is 2.4 × 10^10 N/C.

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To find the electrostatic force that acts on a charge brought to a location with an electric field:

Given:
Electric field strength (E) = 2.8 E 4 N/C (points due south)
Charge (q) = -4.0 E -6 C

The electrostatic force (F) can be calculated using the formula:

F = E × q

Substituting the values into the formula, we have:

F = (2.8 E 4 N/C) × (-4.0 E -6 C)

To simplify the calculation, we can multiply the numbers separately and the exponents separately:

F = (2.8 × (-4.0)) × (10^(4-(-6)))
F = -11.2 × 10^10 N

Therefore, the electrostatic force that acts on the charge is -11.2 × 10^10 N.

To find the magnitude of the electric field at a location, you can use the formula:

Electric Field (E) = Force (F) / Charge (q)

In the given problem, the small piece of lint has a charge of +1.25 E -19 C and is attracted to the socks with a force of 3.0 E -9 N. By rearranging the formula, we can calculate the electric field:

E = F / q

E = (3.0 E -9 N) / (1.25 E -19 C)

E = 2.4 E 10 N/C

Therefore, the magnitude of the electric field at this location is 2.4 E 10 N/C.

For the second problem, to calculate the electrostatic force acting on a charge, you can use the formula:

Force (F) = Electric Field (E) * Charge (q)

In this case, the electric field has a magnitude of 2.8 E 4 N/C and points due south. The charge brought to the location is -4.0 E -6 C. By substituting the values into the formula:

F = (2.8 E 4 N/C) * (-4.0 E -6 C)

F = -1.12 E -1 N

Therefore, the electrostatic force acting on this charge is -1.12 E -1 N. The negative sign indicates that the force is in the opposite direction of the electric field.

Give up on life, and forget trying to understand physics!!!