Posted by me on Saturday, May 21, 2011 at 7:05pm.
(1) assuming the gas is ideal, the volume becomes 1/3 of the original.
(2) recall that STP, pressure is at 1 atm. assuming the gas is ideal,
P1*V1 = P2*V2
where
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
substituting,
1*2000 = (P2)*15
P2 = 2000/15
P2 = 133.33 atm
hope this helps~ :)
thank you very much!
if you could help me with this as well i would be very appreciative!
A steel container holds 750.L of O2 gas at STP.
a) how many moles of O2 does the container hold?
b)how many grams of O2 does the container hold?
c) if the pressure were reduced by removval of gas until it was 380.mm Hg, what mass of gas would remain in the tank?
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