Friday

February 27, 2015

February 27, 2015

Posted by **Mojo** on Saturday, May 21, 2011 at 6:14pm.

- Precalculus -
**MathMate**, Saturday, May 21, 2011 at 10:10pmLet H=horizontal distance to the pole

Vertical distance

=Htan(θ)

where θ is the angle of depression.

Thus

60' = Htan(θ2)-Htan(θ1)

=H(tan(18°)-tan(14°))

Solve for H to get

H = 60'/(tan(18°)-tan(14°))

=?

**Answer this Question**

**Related Questions**

Precalculus - A woman standing on a hill sees a flagpole that she knows to be 60...

trig - A woman standing on a hill sees a flagpole that she knows is 65 ft tall. ...

math - a flagpole is 25 feet tall. a truck runs into the pole and bends it at ...

math - Two pieces of wire are stretched from the top M, of a vertical pole to ...

Math - Trigonomety - A plane is flying at a height of 1000 feet. A passenger on ...

MATH TRIG - FROM A DISTANCE OF 80 M. THE ANGLE OF ELEVATION OF THE TOP OF A ...

Math - A 15 m flagpole stands on level ground. from point P, due west of the ...

Trigo - A vertical pole is standing on a slope that is inclined at an angle 8 ...

precalculus - A radio tower is located 450 feet from a building. From a window ...

Precalculus - 1. A man stands 12 feet from a statue. The angle of elevation from...