Friday

April 18, 2014

April 18, 2014

Posted by **sophie** on Saturday, May 21, 2011 at 4:31pm.

- Math -
**Reiny**, Saturday, May 21, 2011 at 5:52pmPick any point on the first plane, say,

(0,13,0)

distance from that point to

2x + y - 3z - 35 = 0

= |2(0) + 13 - 3(0) - 35|/√(2^2 + 1^2 + (-3)^2)

= 22/√14 or after rationalizing , 11√14/7

- Math -
**bobpursley**, Saturday, May 21, 2011 at 6:11pmsimple. Find a point on the first plane. When x and z are zero, y=13.

Now we find the distance between the point (0,13,0) and the second plane.

d= (2*0+1*13-3*0 -35)/sqrt(4+1+9)

d= 13/sqrt(14)

**Related Questions**

Calculus Grade 12 University - 8. Find the vector equation of the line in which ...

Algebra 2 - Solve the system by elimination: -2x + 2y + 3z = 0 -2x - y + z =-3 ...

algebra - I do not know how to solve the following systems of linear equations ...

math - 4x-y-3z=8 2x+2y-z=3 6x+y-3z=2 help me solve matrices

Calc. - Use normal vectors to determine the intersection, if any, for each of ...

Calc. - Use normal vectors to determine the intersection, if any, for each of ...

pre-calc - solve each system of equations using matrices x+2y-3z=0 2x-4y=z=-7 -...

Math - intersection of planes - You are given the following two planes: x+4y-3z-...

Linear Algebra - 1. Considering 2 planes with equations: x + 2y - 3z = 1 x + 2y...

Linear Algebra - 1. Considering 2 planes with equations: x + 2y - 3z = 1 x + 2y...