How much water must be added to 6.0 mL of a 0.05 M stock solution to dilute it to 0.020 M?
To calculate how much water must be added to dilute a stock solution, we can use the formula:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given:
C1 = 0.05 M (stock concentration)
V1 = 6.0 mL (initial volume)
C2 = 0.020 M (final concentration)
V2 is the final volume, which we need to determine.
Now, let's substitute the given values into the formula and solve for V2:
(0.05 M)(6.0 mL) = (0.020 M)(V2)
0.30 mL = 0.020 M * V2
To find V2, divide both sides of the equation by 0.020 M:
V2 = 0.30 mL / 0.020 M = 15 mL
Therefore, to dilute 6.0 mL of a 0.05 M stock solution to 0.020 M, you need to add approximately 15 mL of water.
To solve this problem, we can use the equation for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration of the stock solution
V1 = initial volume of the stock solution
C2 = final concentration desired
V2 = final volume required after dilution
In this case, we are given:
C1 = 0.05 M
V1 = 6.0 mL
C2 = 0.020 M
V2 = ? (unknown)
Plugging these values into the equation, we get:
(0.05 M) * (6.0 mL) = (0.020 M) * (V2)
To solve for V2, we rearrange the equation:
V2 = (0.05 M * 6.0 mL) / 0.020 M
Now, let's calculate it step by step:
Step 1: Multiply the initial concentration and volume
0.05 M * 6.0 mL = 0.30 mmol
Step 2: Divide the result by the final concentration
0.30 mmol / 0.020 M = 15 mL
Therefore, you need to add 15 mL of water to the 6.0 mL stock solution to dilute it to 0.020 M.
you are diluting it .05/.02=2.5 times. That means, you want one part stock solution, 1.5 parts water.
here one part is 6ml, so you add 9 ml water. Stir, label it as .02M
Now what if it had asked to make 5 ml solution? Still, diluting it 2.5 times, so 2.5 parts into 5 ml is 2 ml per part, so take 2ml of stock solution, and 3 ml of water.