Calculate the mass of NaCl produced when 5.50 moles of Sodium reacts with excess chlorine gas.

4Na + Cl2 yield 2Na2Cl

To calculate the mass of NaCl produced, we need to use the balanced chemical equation for the reaction between sodium and chlorine gas. The balanced equation is:

2 Na + Cl2 -> 2 NaCl

According to the equation, 2 moles of sodium react with 1 mole of chlorine gas to produce 2 moles of sodium chloride.

First, we need to determine the number of moles of sodium chloride produced when 5.50 moles of sodium reacts. Since the mole ratio in the balanced equation is 2:2:1 (2 moles of sodium to 2 moles of sodium chloride to 1 mole of chlorine gas), the number of moles of sodium chloride produced will also be 5.50 moles.

Next, we need to calculate the molar mass of sodium chloride (NaCl), which is the sum of the atomic masses of sodium (Na) and chlorine (Cl). The atomic mass of sodium is 22.99 g/mol, and the atomic mass of chlorine is 35.45 g/mol. Therefore, the molar mass of NaCl is:

22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol

Finally, we can calculate the mass of NaCl produced by multiplying the number of moles of sodium chloride by its molar mass:

Mass of NaCl = Number of moles of NaCl × Molar mass of NaCl
= 5.50 moles × 58.44 g/mol
= 321.42 g

Therefore, the mass of NaCl produced when 5.50 moles of sodium reacts with excess chlorine gas is 321.42 grams.

Here's the equation:

Na + Cl2 -> NaCl
Balance the equation yourself.

stoichiometry:
http://www.jiskha.com/science/chemistry/stoichiometry.html