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Posted by on Saturday, May 21, 2011 at 11:52am.

the only part i cant figure out is the max static friction force that acts on the block. please help show me how to find it


Suppose a block with mass 2.00 kg is resting on a ramp. If the coefficient of static friction between the block and the ramp is 0.320, what maximum angle can the ramp make with the horizontal before the block starts to slip down?

Use the values from PRACTICE IT to help you work this exercise. The ramp in the figure is roughed up and the experiment repeated.
(a) What is the new coefficient of static friction if the maximum angle turns out to be 29.6°?
its 0.567

(b) Find the maximum static friction force that acts on the block.

  • Physics - , Saturday, May 21, 2011 at 11:57am

    force down ramp=force friction up rame
    mgSinTheta=mu*mgCosTheta

    tanTheta=mu

    a) mu=tan29.6

    b) max friction force=mu*mg*cosTheta

  • Physics - , Saturday, May 21, 2011 at 12:26pm

    this equation isnt giving me the right answer :/

  • Physics - , Tuesday, May 22, 2012 at 9:30pm

    Find the fg y component because that is equal to the "n" in the equation:

    F(static friction) = mu x n

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