Friday

November 28, 2014

November 28, 2014

Posted by **Moses joseph** on Saturday, May 21, 2011 at 10:16am.

- statistics -
**TutorCat**, Saturday, May 21, 2011 at 1:52pmtotal balls = 10

without replacement, so you'll have one less ball each time you draw

I'll do the first one for you. You can figure out how to the rest.

P(both black) = (6/10)(5/9)

Explanation: During the first draw, there are 6 black balls and a total of 10 balls. During the second draw (because there was no replacement), there are now 5 black balls and a total of 9 balls.

**Answer this Question**

**Related Questions**

Math - A bag contains 6 black balls,5 red balls and 4 white balls,if 3 are ...

Math - A bag contains 6 black balls,5 red balls and 4 white balls,if 3 are ...

MATH 12 HELP! - One bag contains 4 white balls and 6 black balls. Another bag ...

statistics - A box contains 3 white and 5 black balls. Four balls are drawn at ...

math - there are 6 white balls and 4 black balls.i takeout 2 balls at random,one...

******MATH 12******* - How about this. One bad contains 4 white balls and 6 ...

Math - A bag contains three black balls, four white balls and five red balls. ...

Finite - An urn contains 5 white balls and 4 black balls. If 3 balls are ...

College Discrete - An urn contains n > 0 white balls and m > 0 black ...

MATH Prob. - A box contains two black balls and three gold balls. Two balls are ...