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September 2, 2014

September 2, 2014

Posted by **Moses joseph** on Saturday, May 21, 2011 at 10:16am.

- statistics -
**TutorCat**, Saturday, May 21, 2011 at 1:52pmtotal balls = 10

without replacement, so you'll have one less ball each time you draw

I'll do the first one for you. You can figure out how to the rest.

P(both black) = (6/10)(5/9)

Explanation: During the first draw, there are 6 black balls and a total of 10 balls. During the second draw (because there was no replacement), there are now 5 black balls and a total of 9 balls.

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