Sunday

November 23, 2014

November 23, 2014

Posted by **paul** on Friday, May 20, 2011 at 2:00pm.

- calculus -
**drwls**, Friday, May 20, 2011 at 2:20pmChoose the value of the arbitary constsnt C so that y = 2 when x = 1.

That is all there is to it.

36sqrt2 = 2*[2*18^(3/2)]/3 + C

= 2*(4/3)27*sqrt2) + C

= 72 sqrt2 + C

C = -36 sqrt2

You can write the explicit solution for y(x) by taking the 2/3 root of y^(3/2)/18, with the C term inserted

- calculus -
**paul**, Friday, May 20, 2011 at 2:51pmHello drwls. Please can you explain how you get 72sqrt2+c. Surely, if it is 50.911=50.911+c, if one subtracts either side c=0? Am I missing something?Thank you for your help.

**Answer this Question**

**Related Questions**

calculus - Please help with this question. I have a general solution to a ...

calculus - Please help with this question. I have a general solution to a ...

calculus - Sorry to post this again, but I am still unable to understand it and ...

Calculus - Using 3(x-3)(x^2-6x+23)^1/2, as the chain rule differentiation of f(x...

calculus-differential equation - Consider the differential equation: (du/dt)=-u^...

Differential Equations - The velocity v of a freefalling skydiver is well ...

Maths - Hi I am really sorry I now people have already attempted to help me with...

Math - Solve the differential equation. Let C represent an arbitrary constant...

calculus differential equation - Find in implicit form the general solution of ...

calculus differential equation - Find in implicit form the general solution of ...