Posted by **paul** on Friday, May 20, 2011 at 2:00pm.

Please help. I have an implicit answer to a differential equation of 18y*sqrt(y)=(2(x^2-6x+23)^3/2)/3 plus arbitrary constant. What is the particular solution to this for which y=2 when x=1. And then express this particular solution answer in an explicit form. Please help and many thanks.

- calculus -
**drwls**, Friday, May 20, 2011 at 2:20pm
Choose the value of the arbitary constsnt C so that y = 2 when x = 1.

That is all there is to it.

36sqrt2 = 2*[2*18^(3/2)]/3 + C

= 2*(4/3)27*sqrt2) + C

= 72 sqrt2 + C

C = -36 sqrt2

You can write the explicit solution for y(x) by taking the 2/3 root of y^(3/2)/18, with the C term inserted

- calculus -
**paul**, Friday, May 20, 2011 at 2:51pm
Hello drwls. Please can you explain how you get 72sqrt2+c. Surely, if it is 50.911=50.911+c, if one subtracts either side c=0? Am I missing something?Thank you for your help.

## Answer This Question

## Related Questions

- calculus - Please help with this question. I have a general solution to a ...
- calculus - Please help with this question. I have a general solution to a ...
- calculus - Sorry to post this again, but I am still unable to understand it and ...
- Calculus - Using 3(x-3)(x^2-6x+23)^1/2, as the chain rule differentiation of f(x...
- calculus maths - Hi can some one help, explain the following please. I seem to ...
- Maths - Hi I am really sorry I now people have already attempted to help me with...
- maths - Hi Please can you help Find the particular solution of the differential ...
- maths - Hi Please can you help? Find the particular solution of the differential...
- Maths - Hi Please can you help? Really sorry for repeating the question but I ...
- Maths - Find the particular solution of the differential equation from: dy/dx = ...

More Related Questions