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September 20, 2014

September 20, 2014

Posted by **paul** on Friday, May 20, 2011 at 2:00pm.

- calculus -
**drwls**, Friday, May 20, 2011 at 2:20pmChoose the value of the arbitary constsnt C so that y = 2 when x = 1.

That is all there is to it.

36sqrt2 = 2*[2*18^(3/2)]/3 + C

= 2*(4/3)27*sqrt2) + C

= 72 sqrt2 + C

C = -36 sqrt2

You can write the explicit solution for y(x) by taking the 2/3 root of y^(3/2)/18, with the C term inserted

- calculus -
**paul**, Friday, May 20, 2011 at 2:51pmHello drwls. Please can you explain how you get 72sqrt2+c. Surely, if it is 50.911=50.911+c, if one subtracts either side c=0? Am I missing something?Thank you for your help.

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