Thursday

July 31, 2014

July 31, 2014

Posted by **gabs** on Friday, May 20, 2011 at 10:38am.

ive done this problem every which way i could. specifically i understand that imaginary numbers come in pairs so i wrote: 6+4i, 6-4i, -5+i, -5-i and i put all thos equal to x, subtracted the x so the equation is equal to zero and then began to multipy them .

can someone please write out the steps for me and then give me the format this answer is supposed to be in..PLEASE HELP!

- pre calc -
**Damon**, Friday, May 20, 2011 at 10:57am(x-6+4i)(x-6-4i)(x+5+i)(x+5-i) = 0

(x^2 -12 x + 52)(x^2 + 25 x + 26)

x^4 +13 x^3 -222 x^2 + 988 x +1352

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