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April 20, 2014

April 20, 2014

Posted by **paul** on Thursday, May 19, 2011 at 3:15pm.

- calculus -
**MathMate**, Thursday, May 19, 2011 at 10:17pmCheck if the initial equation is the following:

dy/dx=(2/27)(x-3)√((x^2-6x+23)/y)

27√(y) dy = 2(x-3)√(x^2-6x+23)dx

Integrate both sides and express y in implicit form.

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