Thursday

July 31, 2014

July 31, 2014

Posted by **Luna** on Thursday, May 19, 2011 at 8:45am.

(a) Find the position of the particle after this time.

(b) Find its velocity at the end of this time interval.

Next, assume it moves with simple harmonic motion for 3.50 s and x = 0 is its equilibrium position.

(c) Find its position.

(d) Find its velocity at the end of this time interval.

- Physics -
**drwls**, Thursday, May 19, 2011 at 9:25amSet up the appropriate x(t) or V(t) equation and "plug in" the appropriate t. Thenk crank out the answer. to do, or at least attempt, yourself. Here are the equations:

(a) x = 0.11 t -0.19 t^2

(b) V = 0.11 - 0.38 t

(c) Since t = 3.5 s is the period, it returns to the starting point, x = 0, at that time. You don't need to know the amplitude

(d) Since t = 3.5 s is the period, it returns to the same starting velocity -0.11 m/s

- Physics -
**UNSW BRAH**, Friday, May 20, 2011 at 1:14amhow do you know period is 3.5s

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