A skydiver jumps out of a hovering helicopter, so there is no forward velocity. Ignore wind resistance for this exercise.

1. What is the skydiver's acceleration? (2 points)

9.8 m/s^2

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In this scenario, the only force acting on the skydiver is the force of gravity. According to Newton's second law of motion, the acceleration of an object is equal to the net force acting on it divided by its mass.

Since the skydiver is in freefall, the net force acting on him/her is the force of gravity, which can be calculated using the equation:

F = m * g

Where F is the force of gravity, m is the mass of the skydiver, and g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth).

Therefore, the skydiver's acceleration is also 9.8 m/s^2.

To find the skydiver's acceleration, we need to use the formulas of motion. In this scenario, the skydiver is experiencing freefall, meaning that the only force acting on them is gravity.

The acceleration due to gravity, usually denoted as "g," is approximately 9.8 m/s². This value is constant near the surface of the Earth. Since there are no other forces acting on the skydiver except gravity, their acceleration will be equal to the acceleration due to gravity.

Therefore, the skydiver's acceleration is 9.8 m/s² downward.