Posted by **tj** on Wednesday, May 18, 2011 at 10:44pm.

A 2.00 kg blob of Gak, moving at 4.0 m/s, strikes a motionless figure skater in the back and sticks. The skater, with the Gak on her back, glides off at 0.160 m/s. Calculate the skater’s mass.

- physics -
**drwls**, Wednesday, May 18, 2011 at 11:40pm
Neglect friction (because of the ice skates)and assume conservation of momentum. That results in the equation

2.00*4.0 = (M + 2.00)*0.160

Solve for M, which will be in units of kg

- Physics -
**Total baller**, Thursday, May 30, 2013 at 7:10pm
mvi + mvi(2) = mvf + mvf(2) all energy is conserved

2(4) = (m + 2).16 (the masses are now combined)

8 = .32m

m = 25 kg

your welcome

- physics -
**Bill Smith**, Thursday, May 30, 2013 at 10:35pm
Ok you guys are retarded and definitely do not know your PEMDAS. The correct answer is 48 kg...

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