Posted by tj on Wednesday, May 18, 2011 at 10:44pm.
Neglect friction (because of the ice skates)and assume conservation of momentum. That results in the equation
2.00*4.0 = (M + 2.00)*0.160
Solve for M, which will be in units of kg
mvi + mvi(2) = mvf + mvf(2) all energy is conserved
2(4) = (m + 2).16 (the masses are now combined)
8 = .32m
m = 25 kg
your welcome
mvi + mvi(2) = mvf + mvf(2) all energy is conserved
2(4) = (m + 2).16 (the masses are now combined)
8 = .32m
m = 25 kg
your welcome
Ok you guys are retarded and definitely do not know your PEMDAS. The correct answer is 48 kg...
Related Questions
physics - Two fi gure skaters are moving east together during a performance. ...
physics - A 3.00-kg blob of putty moving at 2.40 m/s slams into a 4.80- g blob ...
physics - Skater 1 has a mass of 45 kg and is at rest. Skater 2 has a mass of 50...
Physics - An ice skater of mass 55.3 kg stops to tie his shoe and is at rest. A ...
physics - A 74.0 kg ice skater moving to the right with a velocity of 2.58 m/s ...
physics - A 74.0 kg ice skater moving to the right with a velocity of 2.58 m/s ...
physics )': - A 66.5 kg ice skater moving to the right with a velocity of 2....
Physics - A 74.5 kg ice skater moving to the right with a velocity of 2.62 m/s ...
Physics - Skater N, 58.9 kg, is moving north at a speed of 7.8 m/s when she ...
Physics - Skater N, 58.9 kg, is moving north at a speed of 7.8 m/s when she ...
For Further Reading