Posted by tenzing on Wednesday, May 18, 2011 at 7:51pm.
during pratice a softball pitcher throws a ball whose height can be modeled by the equation h=16tsquared+24t+1 where h=height in feet and t=time in seconds. how lond does it take for the ball to reach a height of 6 feet?

algebra  Henry, Thursday, May 19, 2011 at 10:38pm
h = 16t^2 + 24t + 1 = 6.
16t^2 + 24t  5 = 0,
Solve for t using the Quadratic Formula
and get:
t = 0.25 and 1.25s.
We have 2 positive solutions for which
I have no explanation.

algebra  john, Monday, May 2, 2016 at 7:28am
Hi,
The reason for two answers is that when the ball is thrown upwards, it reaches a maximum height of 8 feet (i got this using calculus). This means that the balls reaches 6 feet both on the way up, and then on the way down. Hence the two solutions.
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