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during pratice a softball pitcher throws a ball whose height can be modeled by the equation h=-16tsquared+24t+1 where h=height in feet and t=time in seconds. how lond does it take for the ball to reach a height of 6 feet?

  • algebra - ,

    h = -16t^2 + 24t + 1 = 6.
    -16t^2 + 24t - 5 = 0,
    Solve for t using the Quadratic Formula
    and get:

    t = 0.25 and 1.25s.

    We have 2 positive solutions for which
    I have no explanation.

  • algebra - ,


    The reason for two answers is that when the ball is thrown upwards, it reaches a maximum height of 8 feet (i got this using calculus). This means that the balls reaches 6 feet both on the way up, and then on the way down. Hence the two solutions.

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