Posted by **tenzing** on Wednesday, May 18, 2011 at 7:51pm.

during pratice a softball pitcher throws a ball whose height can be modeled by the equation h=-16tsquared+24t+1 where h=height in feet and t=time in seconds. how lond does it take for the ball to reach a height of 6 feet?

- algebra -
**Henry**, Thursday, May 19, 2011 at 10:38pm
h = -16t^2 + 24t + 1 = 6.

-16t^2 + 24t - 5 = 0,

Solve for t using the Quadratic Formula

and get:

t = 0.25 and 1.25s.

We have 2 positive solutions for which

I have no explanation.

- algebra -
**john**, Monday, May 2, 2016 at 7:28am
Hi,

The reason for two answers is that when the ball is thrown upwards, it reaches a maximum height of 8 feet (i got this using calculus). This means that the balls reaches 6 feet both on the way up, and then on the way down. Hence the two solutions.

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