A 50 ohm lamp and a 10 ohm electric iron are connected in series to a generator delivering 120 V.

The current through the lamp and the iron is ___
The voltage ccross the lamp is ___
The voltage drop acrowss the iron is ___

How do I set these up? Thank you.

Rt = 50 + 10 = 60 Ohms.

I = V/Rt = 120 / 60 = 2Amps.

V = IR = 2 * 50 = 100 Volts across lamp.

V = 2 * 10 = 20 Volts across iron.

To solve this problem, you can use Ohm's Law, which states that the current flowing through a circuit is equal to the voltage across the circuit divided by the resistance.

Here's how you can set up the problem:

1. Calculate the total resistance (Rt) of the circuit: Since the lamp and the iron are connected in series, we can add their resistances together. Rt = 50 ohms + 10 ohms = 60 ohms.

2. Calculate the current (I) flowing through the circuit: Use Ohm's Law, I = V / R, where V is the voltage across the circuit and R is the total resistance. I = 120V / 60 ohms = 2 amps.

3. Calculate the voltage (Vlamp) across the lamp: Since the lamp and the iron are in series, the current flowing through them is the same. Therefore, the voltage across the lamp is I * Rlamp, where Rlamp is the resistance of the lamp. Vlamp = 2 amps * 50 ohms = 100 volts.

4. Calculate the voltage drop (Viron) across the iron: Like the voltage across the lamp, the voltage drop across the iron is also I * Riron, where Riron is the resistance of the iron. Viron = 2 amps * 10 ohms = 20 volts.

So the answers to the given questions are:
- The current through the lamp and the iron is 2 amps.
- The voltage across the lamp is 100 volts.
- The voltage drop across the iron is 20 volts.