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September 22, 2014

September 22, 2014

Posted by **mimi** on Wednesday, May 18, 2011 at 4:03pm.

(1+i)^2 (1-i)^3

- calculus -
**bobpursley**, Wednesday, May 18, 2011 at 4:21pmHmmmm.

(1+i)(1-i)(1+i)(1-i)*(1-i)

taking them as pairs...

the first two give (1^-i^2) =2

so we have

2*2*(1-i)

can you take it from here?

Now if you want to do it in polar, the problem is

(1.414@45)^2(1.414@-45)^3=2@90*2@-90*2) * (1-i)=4(1-i) Amazing...same answer

or

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