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calculus

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write it in the form of a+ib
(1+i)^2 (1-i)^3

  • calculus -

    Hmmmm.

    (1+i)(1-i)(1+i)(1-i)*(1-i)

    taking them as pairs...

    the first two give (1^-i^2) =2
    so we have
    2*2*(1-i)

    can you take it from here?

    Now if you want to do it in polar, the problem is
    (1.414@45)^2(1.414@-45)^3=2@90*2@-90*2) * (1-i)=4(1-i) Amazing...same answer
    or

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