March 28, 2017

Post a New Question

Posted by on .

A 7.00 g bullet, when fired from a gun into a 1.00 kg block of wood held in a vice,
penetrates the block to a depth of 8.00 cm. If the block had instead been at rest on a
frictionless horizontal surface, to what depth would the bullet have penetrated?

  • College Physics - ,

    In a frictionless mount, momentum would have been conserved.

    Vfinal for both would be given by
    0.007 Vbullet = (1.007)Vfinal
    Vfinal = 0.00695 Vbullet

    The bullet kinetic energy loss would be
    0.99305^2 = 0.986 of the value lost in the clamped block.

    Assume penetration depth is proportional to kinetic energy loss. This would be true if the stopping force were constant.

    The penetration depth would then be 7.89 cm.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question