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April 18, 2014

April 18, 2014

Posted by **jill** on Tuesday, May 17, 2011 at 9:57pm.

also the ratio length to the width of the alamo isabout 5to 3 if the width of the alamo is 63ft about how long is the alamo? would that be 37.4ft?

THANK YOU.

- math -
**PsyDAG**, Wednesday, May 18, 2011 at 10:57amIt would help if you proofread your questions before you posted them. You indicate

*three*tosses with*four*outcomes.

The probability of any one toss = 1/2

The probability of all/both events occurring = product of the individual events.

If ratio of length to width = 5/3 and width = 63, the length will be > 63.

5/3 = x/63

Solve for x.

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