if freddy tosses a coin three times, what is the probability that the coin will turn up hesds,tails,heads, tails in that order? I came up with 1/2 correct?
also the ratio length to the width of the alamo isabout 5to 3 if the width of the alamo is 63ft about how long is the alamo? would that be 37.4ft?
THANK YOU.
To calculate the probability of a specific sequence of outcomes when tossing a coin, we need to multiply the probabilities of each individual outcome.
1. The probability of getting heads on a single coin toss is 1/2.
2. The probability of getting tails on another coin toss is also 1/2.
3. The probability of getting heads on the third coin toss is 1/2.
4. Finally, the probability of getting tails on the fourth coin toss is again 1/2.
Multiplying these probabilities together gives us:
(1/2) * (1/2) * (1/2) * (1/2) = 1/16
Therefore, the probability of the coin turning up heads, tails, heads, tails in that order is 1/16, not 1/2.
Regarding the second question, if the ratio of length to width of the Alamo is 5 to 3 and the width is 63ft, then we can solve for the length using the following equation:
Length / Width = 5 / 3
Substituting the known values, we have:
Length / 63ft = 5 / 3
Cross-multiplying, we get:
Length = (5/3) * 63ft
Calculating this, we find:
Length = 105ft (rounded to the nearest whole number)
Therefore, the length of the Alamo would be approximately 105ft, not 37.4ft.
To find the probability of a specific coin toss sequence, you multiply the probabilities of each individual toss.
In this case, the probability of getting heads on a single toss is 1/2, and the probability of getting tails is also 1/2.
Therefore, the probability of getting the sequence heads, tails, heads, tails in that specific order would be:
(1/2) * (1/2) * (1/2) * (1/2) = 1/16
So, your initial answer of 1/2 is not correct. The correct probability is 1/16.
Regarding the length of the Alamo, if the ratio of length to width is 5:3 and the width of the Alamo is 63ft, you can set up a proportion to find the length.
Let's call the length L. The ratio of length to width can be written as:
L / 63 = 5 / 3
To solve for L, you cross-multiply and divide:
L = (5 / 3) * 63 = 105
Therefore, the length of the Alamo is 105ft, not 37.4ft.
You're welcome! Let me know if there's anything else I can help you with.
It would help if you proofread your questions before you posted them. You indicate three tosses with four outcomes.
The probability of any one toss = 1/2
The probability of all/both events occurring = product of the individual events.
If ratio of length to width = 5/3 and width = 63, the length will be > 63.
5/3 = x/63
Solve for x.