There is a water reservoir beneath a circular garden to supply a fountain in the garden. The reservoir has a 26-inch diameter. The garden has a 12-foot diameter. How much of the garden doesn't contain the water reservoir?

I have no idea how to do this please explain!!!

Find the areas of both circles. I suggest you use 72 inches instead for the radius of the garden.

A = pi * r^2

i am still confused so you find the areas of both circles, but whats the formula? pi times r times 2? please help me!!!!!

wait so after you find the areas you subtract the reservoir from the garden to get the answer?

A - pi * radius squared

Yes -- subtract the area of the reservoir from the area of the garden.

thanks Jen

To find out how much of the garden doesn't contain the water reservoir, we need to first calculate the area of the garden and the area of the water reservoir.

The area of a circle can be calculated using the formula: A = πr^2, where A is the area and r is the radius of the circle.

Given that the diameter of the garden is 12 feet, we can determine its radius as half of the diameter, which is 12/2 = 6 feet. Therefore, the radius of the garden is 6 feet.

Now, let's calculate the area of the garden:
A_garden = π * (6 feet)^2

To calculate the area of the water reservoir, we need to find its radius first. The diameter of the water reservoir is given as 26 inches. Since the garden and the reservoir are both circular, the radius of the reservoir will be half of the diameter, which is 26/2 = 13 inches. However, to make the units consistent, we need to convert inches to feet. Since 1 foot = 12 inches, we divide 13 inches by 12 to get the radius of the water reservoir in feet, which is 13/12 feet.

Now, let's calculate the area of the water reservoir:
A_reservoir = π * (13/12 feet)^2

To determine the portion of the garden that doesn't contain the water reservoir, we subtract the area of the reservoir from the area of the garden:
Portion_without_reservoir = A_garden - A_reservoir

Now we can substitute the values and calculate the result.

The answer is417.62 after finding the area of both objects and subtracting them