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July 28, 2014

July 28, 2014

Posted by **Kalem** on Tuesday, May 17, 2011 at 4:21pm.

What percent bigger is the perimeter of the new rectangle, compared to the original?

- geometry -
**Reiny**, Tuesday, May 17, 2011 at 5:01pmoriginal area = 54 in^2

new area = 54(2.5) = 135 in^2

Assuming the new rectangle is similar to old one,

length = 9x , width = 6x

54x^2 = 135

x^2 = 2.5

x = √2.5 = 1.58

new length = 9(1.58) = appr. 14.23 in

new width = 6(1.58) = 9.49 in

percentage increase of perimeter = 58%

new perimeter is 158 % of old one

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