Posted by **Kelsey** on Tuesday, May 17, 2011 at 11:55am.

A player kicks a footbal with a velocity of 27 m/s at an angle of 31° with the ground. How high does the ball travel?

- Physics -
**Henry**, Wednesday, May 18, 2011 at 3:03pm
Vo = 27m/s @ 31deg.

Vo(ver) = 27sin31 = 13.91m/s.

Vf = Vo + gt = 0 @ max. height.

13.91 - 9.8t = 0,

9.8t = 13.91,

t = t = 1.42s = time to reach max. ht.

hmax=13.91*1.42 + 0.5*(-9.8*(1.42)^2,

hmax = 19.75 - 9.85 = 9.9m.

## Answer This Question

## Related Questions

- Physics - A man kicks a ball at an angle of 55 degrees above the ground with an ...
- physics - player kicks football from ground level with velocity of32 m/s at an ...
- Physics - Baseball player A bunts the ball by hitting it in such a way that it ...
- Physics! - Baseball player A bunts the ball by hitting it in such a way that it ...
- Physics - Baseball player A bunts the ball by hitting it in such a way that it ...
- Physics - Baseball player A bunts the ball by hitting it in such a way that it ...
- Physics - A player kicks a soccer ball from ground level and sends it flying at ...
- Physics - A soccer player kicks a 0.43 kg ball straight up to see how far it ...
- Physics - A man kicks a soccer ball at an angle of 35 degress above the ground ...
- PHYSICS - A player kicks a ball at an angle of 37 with the horizontal and with ...

More Related Questions