Posted by Ron on Monday, May 16, 2011 at 7:45pm.
A) prob (4reds) = (7/12)(6/11)(5/10)(4/9) = 7/99
or
Prob = C(7,4)/C(12,4) = 35/495 = 7/99
B) could be GGGG, GGGR
Prob = C(5,4)/C(12,4) + C(5,3)*C(7,1)/C(12,4
= 5/495 + 70/495 = 75/495 = 5/33
C) can't have all red or all green
prob = 1 - (all red + all green)
number of all green = C(5,4) = 5
so prob = 1 - (7/99 + 5/495) = 91/99
D) both are labelled 5
prob = C(2,2)*C(10,2)/C(10,4) = 45/495 = 1/11
Related Questions
Probability - An urn contains 7 red marbles labeled {1,2,3,4,5,6,7} and 5 green ...
Mathematics - There are 2 white marbles in urn A and 4 red marbles in urn B . At...
Math - A bag of marbles contains only green and red marbles. All of the marbles ...
Algebra - Out of jar with 100 marbles, 49 are blue marbles, 7 are green marbles...
math - sally has a bag with red,blue, and green marbles. She has twice as many ...
statistics - A box of marbles contains an equal number of red marbles and yellow...
pre-algebra - a bag contains 5 green marbles 2 white marbles 8 blue marbles 9 ...
statistics - Suppose a box of marbles contains an equal number of red marbles ...
Probabilities - A jar contains 2 red marbles, 3 green marbles, 4 blue marbles, ...
Algebra - A box contains 15 blue marbles, 25 yellow marbles, 20 green marbles ...
For Further Reading