Posted by Ron on Monday, May 16, 2011 at 7:45pm.
An urn contains 7 red marbles labeled (1,2,3,4,5,6,7) and 5 green marbles labeled (1,2,3,4,5) four marbles are pulled out at once. what is the probability.
A. all four marbles are red
B. more of the marbles are green than red
C. both red and green marbles are present
D. two of the marbles chosen are both labeled 5

precalculus  Reiny, Monday, May 16, 2011 at 8:13pm
A) prob (4reds) = (7/12)(6/11)(5/10)(4/9) = 7/99
or
Prob = C(7,4)/C(12,4) = 35/495 = 7/99
B) could be GGGG, GGGR
Prob = C(5,4)/C(12,4) + C(5,3)*C(7,1)/C(12,4
= 5/495 + 70/495 = 75/495 = 5/33
C) can't have all red or all green
prob = 1  (all red + all green)
number of all green = C(5,4) = 5
so prob = 1  (7/99 + 5/495) = 91/99
D) both are labelled 5
prob = C(2,2)*C(10,2)/C(10,4) = 45/495 = 1/11
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