Math
posted by Jon on .
Julian has 10 coins. Sue has 5 coins. There is a total of 4 quarters. Sue has more than $1.00. Sue's coins are worth twice as much as Julian's coins.

Unless you include half dollars, Sue must have all 4 quarters to get over $1.00 with 5 coins. the fifth coin can be either a penny nickel or dime. For Julian to have half of Sue's value, her total must be even, so it must be a dime. Can you think of a combination of 10 pennies, nickels or dimes that equals $.55?