Julian has 10 coins. Sue has 5 coins. There is a total of 4 quarters. Sue has more than $1.00. Sue's coins are worth twice as much as Julian's coins.

Unless you include half dollars, Sue must have all 4 quarters to get over $1.00 with 5 coins. the fifth coin can be either a penny nickel or dime. For Julian to have half of Sue's value, her total must be even, so it must be a dime. Can you think of a combination of 10 pennies, nickels or dimes that equals $.55?

To find out the value of Julian's coins, we can assign a variable to represent the value of each coin. Let's say the value of each coin is 'x' dollars.

Given that Julian has 10 coins, we can write the equation: 10x = value of Julian's coins.

Since Sue's coins are worth twice as much as Julian's coins, we can write an equation for Sue's coins: 2(10x) = value of Sue's coins.

We know that there is a total of 4 quarters, and since a quarter is worth $0.25, the value of the quarters is 4 * $0.25 = $1.00.

We are also given that Sue has more than $1.00. Let's say Sue's coins are worth 'y' dollars. So, the equation for Sue's coins is: y > $1.00.

Now we can solve the system of equations to find the values of x and y.

10x + 4 * $0.25 + y > $1.00

Simplifying further:

10x + $1.00 + y > $1.00

10x + y > 0

This equation shows that the sum of Julian's coins (10x) and Sue's coins (y) is greater than 0. However, since we don't have specific values for x or y, we cannot determine the exact amounts of money for Julian and Sue.

Therefore, based on the given information, we can conclude that Julian has 10 coins, Sue has 5 coins, there are 4 quarters, Sue's coins are worth twice as much as Julian's coins, and Sue has more than $1.00.