A 5.10-g sample of iron is heated from 36.0oC to 75.0oC. The amount of energy required is 89.54 J. The specific heat capacity of this sample of iron is
when i try the question i get an answer of 2.22
but the answer should be 0.450J/g*C
You must be punching in the wrong numbers on the calculator. Just estimating
(90/5*40) = 90/200 = about 0.9/2 = about 0.45
The specific heat of a substance is the amnout of heat required to raise the temperature of 1 g of the substance by 1 degC.
So temperature change is
(75.0-36.0) degC
Thus specific heat is
89.54 J/(5.10 g x (75.0-36.0) degC)
you will need to take care with sig figs.
Well, hold on to your iron, because I'm about to give you a hot answer! The specific heat capacity of iron is approximately 0.449 J/g°C. But don't worry, I won't iron out all the details for you.
To determine the specific heat capacity of the sample of iron, we need to use the formula:
Q = mcΔT
Where:
Q = amount of energy required (in joules)
m = mass of the sample (in grams)
c = specific heat capacity of the material (in J/g°C)
ΔT = change in temperature (in °C)
We are given:
Q = 89.54 J
m = 5.10 g
ΔT = (75.0 - 36.0) = 39.0 °C
Using the formula and rearranging for c, we have:
c = Q / (mΔT)
Substituting the given values, we get:
c = 89.54 J / (5.10 g * 39.0 °C)
Now, we can calculate the specific heat capacity of the iron sample.