Tuesday

January 27, 2015

January 27, 2015

Posted by **Lee** on Sunday, May 15, 2011 at 2:18pm.

- algebra -
**drwls**, Sunday, May 15, 2011 at 3:37pmIt makes no sense to me. It says the price went from +x to -3x, so they are paying you three times the original price just to give them away.

Since the cell carriers make their big money on the service charges, sometimes such giveaways make sense.

I suspect whoever wrote that question does not know what a 400% decrease means.

- algebra -
**Lee**, Sunday, May 15, 2011 at 4:26pmThanks for the input.

- algebra -
**Marcus**, Wednesday, February 6, 2013 at 11:22pmActually is does make sense. drwls misinterpreted the question. It's asking for a decrease of 400% over 10 year and NOT a percent decrease. This means, that for year 1, the cost of a cell phone drop by 40%. At year 2 it dropped by another 40%, and on and on until year 10. So 40%+40%+40%+40%+40%+40%+40%+40%+40%+40% = 400%.

So assume at year 1 the cost of a phone is $100. Then at year 2 it will be $60 since (1-0.4)*100=60. Using the same process, at year 3 it will be $36....Finally, at year 10, it's $1.00.

This is not the same as claim the prince dropped by 4 time over 10 years.

**Answer this Question**

**Related Questions**

algebra - If the cost of a cell phone has decreased 400% during the past 10 ...

algebra - If the cost of a cell phone has decreased 400% during the past 10 ...

Algebra - If the cost of a cell phone has decreased 400% during the past 10 ...

ALGEBRA - If the cost of a cell phone has decreased 400% during the past 10 ...

math - If the cost of a cell phone has decreased 400% during the past 10 years, ...

algebra - If the cost of a cell phone has decreased 400% during the last 10 ...

MAT 116 (algebra) - Please help not understanding this question. If the cost of ...

algebra - If the cost of a cell phone has decrease 400% during the past 10 years...

math - If the cost of a cell phone has decreased 20% a year during the past 10 ...

algebra - Hi I need a formula for the following word problem. The cost of a ...