How many grams of sodium cyanide would be required to make 55 grams of sodium sulfate?

Worked example. Just follow the steps.

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55 grams also. Because according to law of conservation of mass,the mass of the reactant is equal to the mass of the product.

To determine the amount of grams of sodium cyanide required to make 55 grams of sodium sulfate, we need to calculate the molar ratio between the two compounds.

Step 1: Obtain the molar mass of sodium cyanide (NaCN) and sodium sulfate (Na2SO4).
- The molar mass of sodium cyanide (NaCN) is calculated by summing the atomic masses of its constituents: Na (22.99 g/mol) + C (12.01 g/mol) + N (14.01 g/mol) = 46.01 g/mol.
- The molar mass of sodium sulfate (Na2SO4) is calculated by summing the atomic masses of its constituents: Na (22.99 g/mol) + S (32.07 g/mol) + 4O (16.00 g/mol) = 142.04 g/mol.

Step 2: Determine the molar ratio between sodium cyanide (NaCN) and sodium sulfate (Na2SO4).
- The molar ratio between sodium cyanide and sodium sulfate can be derived from the balanced chemical equation of their synthesis reaction. Assuming the reaction is:
2NaCN + Na2SO4 -> 2Na2SO4 + Na2S + CO2 + N2

From the equation, we identify that 2 moles of sodium cyanide (NaCN) react with 1 mole of sodium sulfate (Na2SO4) to produce 2 moles of sodium sulfate (Na2SO4). Therefore, the molar ratio between sodium cyanide and sodium sulfate is 2:1.

Step 3: Calculate the amount of sodium cyanide required.
- Since the molar ratio between sodium cyanide (NaCN) and sodium sulfate (Na2SO4) is 2:1, we need twice the number of moles of sodium cyanide compared to sodium sulfate to maintain this ratio.
- The number of moles of sodium sulfate is calculated by dividing the given mass (55 grams) by the molar mass of sodium sulfate (142.04 g/mol):
Moles of Na2SO4 = Mass of Na2SO4 / Molar mass of Na2SO4 = 55 g / 142.04 g/mol

- To find the moles of sodium cyanide required, we multiply the moles of sodium sulfate by the molar ratio:
Moles of NaCN = 2 × Moles of Na2SO4 = 2 × (55 g / 142.04 g/mol)

Step 4: Calculate the grams of sodium cyanide required.
- Finally, we can calculate the mass of sodium cyanide needed by multiplying the moles of sodium cyanide by its molar mass:
Mass of NaCN = Moles of NaCN × Molar mass of NaCN = (2 × (55 g / 142.04 g/mol)) × 46.01 g/mol

By performing the calculations, you will be able to determine the grams of sodium cyanide required to make 55 grams of sodium sulfate.