Monday

October 20, 2014

October 20, 2014

Posted by **Jennifer** on Sunday, May 15, 2011 at 10:21am.

I can't seem to come up with the correct equation. I'm using the formula y=a(h-k)^2+k but I'm not doing something right. Can anyone help me?

- Algebra -
**Jai**, Sunday, May 15, 2011 at 10:42amthe formula is wrong. it should be

y = a(x-h)^2 + k

where (h,k) is the center

then to solve for a, you choose one of the points to substitute for the value of x and y. for instance you choose (-4,-1):

y = a(x-h)^2 + k

-1 = a(-4+3)^2 - 2

then solve for a.

if you want to make sure that you got the correct points on the parabola, if they are substituted in the equation, they should give the same value of a.

hope this helps~ :)

**Answer this Question**

**Related Questions**

Algebra 1 parabola's - I have a graph with a parabola on it and asked to write ...

pre cal - What is the center of the conic whose equation is x^2 + 2y^2 - 6x + ...

Algebra - I have a graph here. The vertex is (4,-4), then the points (3,-3) and...

algebra - Suppose a parabola has a vertex (-4,7) and also passes through the ...

math help,algebra - Okay this is what i have to do but i think i am doing ...

algebra 2 please check - Write an equation for a parabola with vertex at (-4 , 3...

Algebra II - Write an equation for the parabola with focus (1,3) and vertex (0,3...

math - write an equation for the parabola with focus (1,3) and vetex (0,3) See ...

algebra - 1)What is the distance between the museum and sailing club.I cant post...

Maths - Hi, need a bit of help on this one. A straight line passes through the ...