Posted by **Kandee Johnson** on Sunday, May 15, 2011 at 5:22am.

1. Let (-7, 4) be a point on the terminal side of (theta). Find the exact values of sin(theta), csc(theta), and cot(theta).

2. Let (theta) be an angle in quadrant IV such that sin(theta)=-2/5. Find the exact values of sec(theta) and tan(theta).

3. Let (theta) be an angle in quadrant II such that csc(theta)=7/4. Find the exact values of tan(theta) and cos(theta).

4. Use a cofunction to write an expression equal to csc(3pi/8).

Thank You <3

- Math -
**Reiny**, Sunday, May 15, 2011 at 10:33am
1. (-7,4) is in quadrants II,

so x=-7, y = 4

by Pythagoras, r = √(49 = 16) = √65

sinØ = y/r = 4/√65

cscØ = r/y = √65/4

cotØ = x/y = -7/4

2. since sinØ = -2/5 and Ø is in IV,

y = -2, r = 5, then x^2 + 4 = 25

x = √21

etc.

can you finish the rest?

- Math -
**Anonymous**, Tuesday, January 15, 2013 at 3:08am
:(

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