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September 1, 2014

September 1, 2014

Posted by **melissa** on Saturday, May 14, 2011 at 11:42pm.

- math -
**Mgraph**, Sunday, May 15, 2011 at 1:53amLet x- is the side of the barn.

The area of the yard

A(x)=x*(120-x)/2=60x-x^2/2

A'(x)=60-x=0 => x=60,(120-x)/2=30

max A=1800m^2

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