Posted by **Sue** on Saturday, May 14, 2011 at 8:51pm.

What is the heat in Joules required to raise the temperature of 100g H20 from 288K to 308K?

- Chemistry -
**Jai**, Saturday, May 14, 2011 at 9:08pm
to get the heat released or absorbed,

Q = mc(T2-T1)

where

m = mass of substance (units in g)

c = specific heat capacity (units in J/g-K)

T2 = final temperature

T1 = initial temperature

**note: if Q is (-), heat is released and if (+), heat is absorbed

for water c = 4.184 J/g-K

substituting,

Q = 100*4.184*(308-288)

Q = 8368 J

hope this helps~ :)

- Chemistry -
**Ben**, Thursday, December 15, 2016 at 10:37am
8368J

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