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April 19, 2014

April 19, 2014

Posted by **Rachal** on Saturday, May 14, 2011 at 7:18pm.

Find all solutions of the equation in the interval [0,2pi].

(2cosè+sqrt3)(cscè+1)=0

Write your answer in radians in terms of pi.

If there is more than one solution, separate them with commas.

- Trig -
**Damon**, Saturday, May 14, 2011 at 8:19pmzero if either

2 cos e + sqrt 3 = 0

or if

csc e = -1

for the first (in quadrants 2 and 3 for - cos)

cos e = - sqrt 3/2

that in degrees is 180-30 or 180+30

in radians it is pi +/- pi/6

for the second sin is - so quadrants 3 and 4)

1/sin e = -1

sin e = -1

pi/2 and -pi/2

- Trig -
**Rachal**, Saturday, May 14, 2011 at 9:08pmthanks!

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