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Trig

posted by on .

I need help, I don't remember what to do.
Find all solutions of the equation in the interval [0,2pi].
(2cosè+sqrt3)(cscè+1)=0

Write your answer in radians in terms of pi.
If there is more than one solution, separate them with commas.

  • Trig - ,

    zero if either
    2 cos e + sqrt 3 = 0
    or if
    csc e = -1

    for the first (in quadrants 2 and 3 for - cos)
    cos e = - sqrt 3/2
    that in degrees is 180-30 or 180+30
    in radians it is pi +/- pi/6

    for the second sin is - so quadrants 3 and 4)
    1/sin e = -1
    sin e = -1
    pi/2 and -pi/2

  • Trig - ,

    thanks!

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