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December 20, 2014

December 20, 2014

Posted by **shawn** on Saturday, May 14, 2011 at 11:40am.

- trig -
**Anonymous**, Saturday, May 14, 2011 at 12:09pmThe cosine is positive in I and IV

quadrant,negative in II and III quadrant.

The tangent is positive in I and III guadrant,negative in II and IV quadrant.

If cos(theta)<0 cosine is negative

If tan(theta)>0 tangent is positive

Only quadrant where cosine is nagative,and tangent is positive is quadrant III.

sin(theta)= + OR - sqroot[1-cos^2(theta)]

In quadrant III sine is negative so:

sin(theta)= - sqroot[1-cos^2(theta)]

sin(theta)= - sqroot[1-(-1/2)^2]

sin(theta)= - sqroot(1-1/4)

sin(theta)= - sqroot(3/4)

sin(theta)= - sqroot(3) /2

tan(theta)=sin(theta)/cos(theta)=

[-sqroot(3)/2]/(-1/2)= + sqroot(3)=

sqroot(3)

ctg(theta)=1/tan(theta)=1/sqroot(3)

sec(theta)=1/cos(theta)=1/(-1/2)= -2

cosec(theta)=1/sin(theta)=1/[-sqroot(3) /2]= -2/sqroot(3)

- trig -
**anna**, Tuesday, October 4, 2011 at 10:23pmdetermine all trig functions of theta using the given info, state the answers correct to the nearest hundredth.

cos (theta) = -5/13; tan (theta) < 0

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