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Calculus

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This is the questions I have trouble with :

Set up (do not evaluate) the integral that gives the surface area of the surface generated by rotating the curve y=tanhx on the interval (0, 1) around the x-axis.

Anyone who can help? Not really sure how to even begin!
Thanks

  • Calculus - ,

    Surface area will be y dx dTheta

    from x 0 to 1, and theta from 0 to 2PI


    Area= Int (Int) tanhx dx dtheta

  • Calculus - ,

    Area=2Pi(int from 0 to 1) y*sqrt(1+(y')^2)dx

  • Calculus - ,

    Thanks so much! :)

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