Posted by **Laura** on Friday, May 13, 2011 at 6:32pm.

This is the questions I have trouble with :

Set up (do not evaluate) the integral that gives the surface area of the surface generated by rotating the curve y=tanhx on the interval (0, 1) around the x-axis.

Anyone who can help? Not really sure how to even begin!

Thanks

- Calculus -
**bobpursley**, Friday, May 13, 2011 at 6:37pm
Surface area will be y dx dTheta

from x 0 to 1, and theta from 0 to 2PI

Area= Int (Int) tanhx dx dtheta

- Calculus -
**Mgraph**, Friday, May 13, 2011 at 8:24pm
Area=2Pi(int from 0 to 1) y*sqrt(1+(y')^2)dx

- Calculus -
**Laura**, Friday, May 13, 2011 at 8:41pm
Thanks so much! :)

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