Post a New Question


posted by .

This is the questions I have trouble with :

Set up (do not evaluate) the integral that gives the surface area of the surface generated by rotating the curve y=tanhx on the interval (0, 1) around the x-axis.

Anyone who can help? Not really sure how to even begin!

  • Calculus -

    Surface area will be y dx dTheta

    from x 0 to 1, and theta from 0 to 2PI

    Area= Int (Int) tanhx dx dtheta

  • Calculus -

    Area=2Pi(int from 0 to 1) y*sqrt(1+(y')^2)dx

  • Calculus -

    Thanks so much! :)

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question