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January 28, 2015

January 28, 2015

Posted by **olek** on Friday, May 13, 2011 at 2:03pm.

dy/dx=(1+2cos^2(x))/y, (y > 0), y= 1 when x = 0.

Thanks.

- maths -
**Mgraph**, Friday, May 13, 2011 at 2:27pmIs it an answer on my question?

2cos^2(x)=1+cos(2x)

ydy=(2+cos(2x))dx integrating

y^2/2=2x+sin(2x)/2+C Find C

1/2=C

y=sqrt(4x+sin(2x)+1)

- maths -
**albert**, Friday, May 13, 2011 at 2:42pmThats right.

Thank you.

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