Posted by **Jodi** on Friday, May 13, 2011 at 7:50am.

Please help-What is the equation of the ellipse with foci (0,6), (0,-6) and co-vertices (2,0),(-2,0)

Please explain the steps because I have 5 to do for homework-Thank you-I'm really stuck on this

I thought the answer would be x^2/4 + y^2/40 = 1 but that can't be because the choices are:

x^2/1 + y^2/40 = 1 or x^2/1 + y^2/36

I'm really confused

- Algebra II Please check- -
**Jodi**, Friday, May 13, 2011 at 8:11am
I forgot to put that I think b= 2

c=6, so therefore

a^2-2^2 = 6^2

so a= 40, that' how I got to my equation

- Algebra II Please check- -
**Mgraph**, Friday, May 13, 2011 at 8:40am
Your answer is correct.

- Algebra II-it can't be correct- Please check- -
**Jodi**, Friday, May 13, 2011 at 8:51am
It can't be correct my equation because that isn't a choice I was given-that's what I don't understand-thanks for trying to help though

- Algebra II Please check- -
**Henry**, Saturday, May 14, 2011 at 5:05pm
Jodi,my answer was exactly identical to

yours.

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