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July 28, 2014

July 28, 2014

Posted by **lea** on Friday, May 13, 2011 at 6:44am.

Help me pls..

- geometry -
**drwls**, Friday, May 13, 2011 at 7:25ampi*D^2*L is the same for both.

Therefore D1^2*L1 = D2^2*L2

and D1^3 = 2D2^3

Therefore D2/D1 = 1.260

For the areas,

A1 = pi*D1^2/2 + pi*D1*L

= (3/2)pi*D1^2 since D1 = L1

A2 = pi*D2^2/2 + pi*D2*L2

= (5/2)pi*D2^2 since D2 = 2L2

A2/A1 = (5/3)*(D2/D1)^2

= (5/3)*1.5873 = 2.646

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