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August 31, 2014

August 31, 2014

Posted by **Abigail** on Friday, May 13, 2011 at 12:15am.

f(x) =cos^-1(x^2)

Ok so I'm having a little confusion with the chain rule and I'm not sure if my answer is right...

will the answer be... 2x(-cos^-2(x^2)(-sin(x^2)?

- Calculus -
**Jai**, Friday, May 13, 2011 at 12:42amrecall that the derivative of cos^-1 (x) or arccos (x) is

-1/[sqrt(1-x^2)] * dx

thus the derivative of cos^-1 (x^2)

-(2x)/[sqrt(1 - x^4)]

note that the 2x is the dx that came from the derivatice of the term inside the cos^-1, which is x^2.

hope this helps~ :)

- Calculus -
**Bosnian**, Friday, May 13, 2011 at 12:59amIn google type:

calc101

When you see list of results click on first link.

When page be open click option derivatives.

When that page be open in rectangle type your function and click option DO IT.

You will see solution step by step.

- Calculus -
**Bosnian**, Friday, May 13, 2011 at 1:00amIf cos^-1(x^2) mean 1/cos(x^2)

type cos[x^2]^(-1)

If cos^-1(x^2) mean arccos(x^2)

type arccos[x^2]

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