Posted by sophie on Thursday, May 12, 2011 at 9:25pm.
Given the plane 2x3y+7z=4,
a) Find the equation for the line perpendicular to the plane that intersects the plane at the point P=(6,5,1).
b) How far is it from the point (4,2,3) to the plane?

math  Mgraph, Thursday, May 12, 2011 at 10:07pm
a)(x6)/2=(y5)/(3)=(z1)/7
b)The normal equation of the plane
(2/sqrt(62))x(3/sqrt(62))y+(7/sqrt(62))z
4/sqrt(62)=0 62=2^2+(3)^2+7^2
The distance=(2*43*(2)+7*34)/sqrt(62)=
sqrt(31/2)

math  sophie, Thursday, May 12, 2011 at 10:26pm
why do you have = signs in part a?
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