Posted by sophie on Thursday, May 12, 2011 at 9:25pm.
a)(x-6)/2=(y-5)/(-3)=(z-1)/7
b)The normal equation of the plane
(2/sqrt(62))x-(3/sqrt(62))y+(7/sqrt(62))z-
-4/sqrt(62)=0 62=2^2+(-3)^2+7^2
The distance=(2*4-3*(-2)+7*3-4)/sqrt(62)=
sqrt(31/2)
why do you have = signs in part a?
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