Posted by **olek** on Thursday, May 12, 2011 at 7:36pm.

give the solution of the initial-value problem

dx/dy=(1+2cos^2(x))/y, (y > 0), y= 1 when x = 0.

Thanks.

- maths -
**Mgraph**, Thursday, May 12, 2011 at 8:55pm
dx/dy or dy/dx ?

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