Posted by vivian on Thursday, May 12, 2011 at 7:23pm.
If we all codeine, C, then the hydrolysis is
C + HOH ==> HC^+ + OH^-
Kb = (Kw/Ka) = (OH^-)^2/(C)
Substitute into the Kb expression and solve for OH^-, convert to pOH, then to pH.
Related Questions
chemistry - Calculate the pH and percentage protonation of the solute in an ...
Chemistry - Calculate the pOH, pH, and percent protonation of solute in the ...
Chemistry - Calculate the pOH, pH, and percent protonation of solute in the ...
Chemistry - An aqueous solution is 8.50% ammonium chloride, NH4Cl, by mass. The...
chemistry - determine the amounts of solute and solvent needed to prepare the ...
chemistry - Here are 2 questions I worked out, but need them checked. Also, can...
chemistry lab - Here are 2 questions I worked out, but need them checked. Also, ...
chemistry - Hi, The problem is: "Calculate the concentration of OH- and the...
Chemistry - a solution is made by combining 10.0 ml of 17.5 M acetic acid with 5...
chemistry - What is the pH of an aqueous solution of a weakly acidic drug that ...
For Further Reading
