Posted by Brandon on .
Show that the following numbers are irrational:
1. sqrt3
2. sqrt6

Algebra 2 
Mgraph,
1. Let sqrt3=m/n where m,nrelatively
primes.
3n^2=m^2 ==>m multiple of 3, m=3k
3n^2=9k^2
n^2=3k^2 ==>n multiple of 3.