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November 28, 2014

November 28, 2014

Posted by **Brandon** on Thursday, May 12, 2011 at 6:26pm.

1. sqrt3

2. sqrt6

- Algebra 2 -
**Mgraph**, Thursday, May 12, 2011 at 8:01pm1. Let sqrt3=m/n where m,n-relatively

primes.

3n^2=m^2 ==>m multiple of 3, m=3k

3n^2=9k^2

n^2=3k^2 ==>n multiple of 3.

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