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March 30, 2017

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Show that the following numbers are irrational:

1. sqrt3
2. sqrt6

  • Algebra 2 - ,

    1. Let sqrt3=m/n where m,n-relatively
    primes.
    3n^2=m^2 ==>m multiple of 3, m=3k
    3n^2=9k^2
    n^2=3k^2 ==>n multiple of 3.

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