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posted by Brandon on Thursday, May 12, 2011 at 6:26pm.
Show that the following numbers are irrational: 1. sqrt3 2. sqrt6
1. Let sqrt3=m/n where m,n-relatively primes. 3n^2=m^2 ==>m multiple of 3, m=3k 3n^2=9k^2 n^2=3k^2 ==>n multiple of 3.
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