Posted by **vivian** on Thursday, May 12, 2011 at 6:05pm.

Calculate the solubility product of calcium hydroxide if the solubility of Ca(OH)2(s) in water at 25◦C is 0.011 M.

Choices:

1. 1.1 × 10−5

2. 5.3 × 10−6

3. 2.7 × 10−6

4. 1.5 × 10−8

5. 1.2 × 10−4

- chemistry(Acid&Base) -
**DrBob222**, Thursday, May 12, 2011 at 6:22pm
Ca(OH)2 ==> Ca^2+ + 2OH^-

Ksp = (Ca^2+)(OH^=)^2

Set up an ICE chart, substitute into the Ksp expression and solve for Ksp.

The problem tells you that the solubility of Ca(OH)2 is 0.011M, therefore, (Ca^2+) must be 0.011M and (OH^-) must be twice that. Plug and chug.

- chemistry(Acid&Base) -
**vivian**, Thursday, May 12, 2011 at 7:20pm
is the answer 2)5.3....

- chemistry(Acid&Base) -
**DrBob222**, Thursday, May 12, 2011 at 8:08pm
The answer is (2) but that is 5.3E-6 and not just 5.3.

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