Posted by vivian on Thursday, May 12, 2011 at 6:05pm.
Ca(OH)2 ==> Ca^2+ + 2OH^-
Ksp = (Ca^2+)(OH^=)^2
Set up an ICE chart, substitute into the Ksp expression and solve for Ksp.
The problem tells you that the solubility of Ca(OH)2 is 0.011M, therefore, (Ca^2+) must be 0.011M and (OH^-) must be twice that. Plug and chug.
is the answer 2)5.3....
The answer is (2) but that is 5.3E-6 and not just 5.3.
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