find the area of a triangle whose sides are 25,25, and 14
answer is not 175 but 168
need help
To find the area of a triangle, you can use Heron's formula. Heron's formula states that the area (A) of a triangle with sides a, b, and c can be calculated using the semi-perimeter (s) of the triangle, which is the sum of all sides divided by 2:
s = (a + b + c) / 2
With the semi-perimeter, you can use the following formula to calculate the area of the triangle:
A = √(s(s-a)(s-b)(s-c))
Let's calculate the area of the given triangle with sides 25, 25, and 14.
1. Calculate the semi-perimeter (s):
s = (25 + 25 + 14) / 2
s = 64 / 2
s = 32
2. Substitute the values into the formula to find the area (A):
A = √(32(32-25)(32-25)(32-14))
A = √(32 * 7 * 7 * 18)
A = √(32 * 7^2 * 18)
A = √(32 * 49 * 18)
A = √28224
A ≈ 168.14
Therefore, the area of the triangle is approximately 168.14 square units.
92.87
area= 1/2(b)(h)
h=sqrt(15^2-7^2)
h=13.27
b=14
area= 1/2(b)(h)
area= 1/2(14)(13.27)
area= 92.87
area= 1/2(b)(h)
area= 1/2(25)(14)
area= 1/2(350)
area= 175